x-2*(x-2)+6=+3*(x-3)+x

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Solution for x-2*(x-2)+6=+3*(x-3)+x equation: 



x-2(x-2)+6=+3(x-3)+x

We move all terms to the left:

x-2(x-2)+6-(+3(x-3)+x)=0

We multiply parentheses

x-2x-(+3(x-3)+x)+4+6=0



We calculate terms in parentheses: -(+3(x-3)+x), so:

+3(x-3)+x

determiningTheFunctionDomain
3(x-3)+x

We add all the numbers together, and all the variables

x+3(x-3)

We multiply parentheses

x+3x-9

We add all the numbers together, and all the variables

4x-9

Back to the equation:

-(4x-9)



We add all the numbers together, and all the variables

-1x-(4x-9)+10=0

We get rid of parentheses

-1x-4x+9+10=0

We add all the numbers together, and all the variables

-5x+19=0

We move all terms containing x to the left, all other terms to the right

-5x=-19

x=-19/-5

x=3+4/5

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