x-2(x-3)=4(2x+3)-(x-4)

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Solution for x-2(x-3)=4(2x+3)-(x-4) equation: 



x-2(x-3)=4(2x+3)-(x-4)

We move all terms to the left:

x-2(x-3)-(4(2x+3)-(x-4))=0

We multiply parentheses

x-2x-(4(2x+3)-(x-4))+6=0



We calculate terms in parentheses: -(4(2x+3)-(x-4)), so:

4(2x+3)-(x-4)

We multiply parentheses

8x-(x-4)+12

We get rid of parentheses

8x-x+4+12

We add all the numbers together, and all the variables

7x+16

Back to the equation:

-(7x+16)



We add all the numbers together, and all the variables

-1x-(7x+16)+6=0

We get rid of parentheses

-1x-7x-16+6=0

We add all the numbers together, and all the variables

-8x-10=0

We move all terms containing x to the left, all other terms to the right

-8x=10

x=10/-8

x=-1+1/4

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