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x-2(x+3)=10
We move all terms to the left:
x-2(x+3)-(10)=0
We multiply parentheses
x-2x-6-10=0
We add all the numbers together, and all the variables
-1x-16=0
We move all terms containing x to the left, all other terms to the right
-x=16
x=16/-1
x=-16
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