x-2(x+1)=8-3(x+1)

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Solution for x-2(x+1)=8-3(x+1) equation: 



x-2(x+1)=8-3(x+1)

We move all terms to the left:

x-2(x+1)-(8-3(x+1))=0

We multiply parentheses

x-2x-(8-3(x+1))-2=0



We calculate terms in parentheses: -(8-3(x+1)), so:

8-3(x+1)

determiningTheFunctionDomain
-3(x+1)+8

We multiply parentheses

-3x-3+8

We add all the numbers together, and all the variables

-3x+5

Back to the equation:

-(-3x+5)



We add all the numbers together, and all the variables

-1x-(-3x+5)-2=0

We get rid of parentheses

-1x+3x-5-2=0

We add all the numbers together, and all the variables

2x-7=0

We move all terms containing x to the left, all other terms to the right

2x=7

x=7/2

x=3+1/2

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