x-2(3x-5)=4x+6(x-4)

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Solution for x-2(3x-5)=4x+6(x-4) equation: 



x-2(3x-5)=4x+6(x-4)

We move all terms to the left:

x-2(3x-5)-(4x+6(x-4))=0

We multiply parentheses

x-6x-(4x+6(x-4))+10=0



We calculate terms in parentheses: -(4x+6(x-4)), so:

4x+6(x-4)

We multiply parentheses

4x+6x-24

We add all the numbers together, and all the variables

10x-24

Back to the equation:

-(10x-24)



We add all the numbers together, and all the variables

-5x-(10x-24)+10=0

We get rid of parentheses

-5x-10x+24+10=0

We add all the numbers together, and all the variables

-15x+34=0

We move all terms containing x to the left, all other terms to the right

-15x=-34

x=-34/-15

x=2+4/15

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