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x-2(3x)=x+4(x-1)
We move all terms to the left:
x-2(3x)-(x+4(x-1))=0
We add all the numbers together, and all the variables
-22x-(x+4(x-1))=0
We calculate terms in parentheses: -(x+4(x-1)), so:We get rid of parentheses
x+4(x-1)
We multiply parentheses
x+4x-4
We add all the numbers together, and all the variables
5x-4
Back to the equation:
-(5x-4)
-22x-5x+4=0
We add all the numbers together, and all the variables
-27x+4=0
We move all terms containing x to the left, all other terms to the right
-27x=-4
x=-4/-27
x=4/27
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