x-2(2x-5)=2(x+3)-8

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Solution for x-2(2x-5)=2(x+3)-8 equation: 



x-2(2x-5)=2(x+3)-8

We move all terms to the left:

x-2(2x-5)-(2(x+3)-8)=0

We multiply parentheses

x-4x-(2(x+3)-8)+10=0



We calculate terms in parentheses: -(2(x+3)-8), so:

2(x+3)-8

We multiply parentheses

2x+6-8

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

-3x-(2x-2)+10=0

We get rid of parentheses

-3x-2x+2+10=0

We add all the numbers together, and all the variables

-5x+12=0

We move all terms containing x to the left, all other terms to the right

-5x=-12

x=-12/-5

x=2+2/5

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