x-16-3(x+28)=12-6(x-20)

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Solution for x-16-3(x+28)=12-6(x-20) equation: 



x-16-3(x+28)=12-6(x-20)

We move all terms to the left:

x-16-3(x+28)-(12-6(x-20))=0

We multiply parentheses

x-3x-(12-6(x-20))-84-16=0



We calculate terms in parentheses: -(12-6(x-20)), so:

12-6(x-20)

determiningTheFunctionDomain
-6(x-20)+12

We multiply parentheses

-6x+120+12

We add all the numbers together, and all the variables

-6x+132

Back to the equation:

-(-6x+132)



We add all the numbers together, and all the variables

-2x-(-6x+132)-100=0

We get rid of parentheses

-2x+6x-132-100=0

We add all the numbers together, and all the variables

4x-232=0

We move all terms containing x to the left, all other terms to the right

4x=232

x=232/4

x=58

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