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x-12=2-3(x-2)
We move all terms to the left:
x-12-(2-3(x-2))=0
We calculate terms in parentheses: -(2-3(x-2)), so:We get rid of parentheses
2-3(x-2)
determiningTheFunctionDomain -3(x-2)+2
We multiply parentheses
-3x+6+2
We add all the numbers together, and all the variables
-3x+8
Back to the equation:
-(-3x+8)
x+3x-8-12=0
We add all the numbers together, and all the variables
4x-20=0
We move all terms containing x to the left, all other terms to the right
4x=20
x=20/4
x=5
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