x-12+3x=3-2(x+18)

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Solution for x-12+3x=3-2(x+18) equation: 



x-12+3x=3-2(x+18)

We move all terms to the left:

x-12+3x-(3-2(x+18))=0

We add all the numbers together, and all the variables

4x-(3-2(x+18))-12=0



We calculate terms in parentheses: -(3-2(x+18)), so:

3-2(x+18)

determiningTheFunctionDomain
-2(x+18)+3

We multiply parentheses

-2x-36+3

We add all the numbers together, and all the variables

-2x-33

Back to the equation:

-(-2x-33)



We get rid of parentheses

4x+2x+33-12=0

We add all the numbers together, and all the variables

6x+21=0

We move all terms containing x to the left, all other terms to the right

6x=-21

x=-21/6

x=-3+1/2

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