x-1/5+3(x+2)=x/2

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Solution for x-1/5+3(x+2)=x/2 equation: 


x in (-oo:+oo)

3*(x+2)+x-(1/5) = x/2 // - x/2

3*(x+2)+x-(x/2)-(1/5) = 0

3*(x+2)+x-(x/2)-1/5 = 0

3*(x+2)+x-x/2-1/5 = 0

(2*3*5*(x+2))/(2*5)+(2*5*x)/(2*5)+(5*(-x))/(2*5)+(-1*2)/(2*5) = 0

2*3*5*(x+2)+2*5*x+5*(-x)-1*2 = 0

40*x-5*x-2+60 = 0

35*x-2+60 = 0

35*x+58 = 0

(35*x+58)/(2*5) = 0

(35*x+58)/(2*5) = 0 // * 2*5

35*x+58 = 0

35*x+58 = 0 // - 58

35*x = -58 // : 35

x = -58/35

x = -58/35

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