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x-1/3x=3000
We move all terms to the left:
x-1/3x-(3000)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
x*3x-3000*3x-1=0
Wy multiply elements
3x^2-9000x-1=0
a = 3; b = -9000; c = -1;
Δ = b2-4ac
Δ = -90002-4·3·(-1)
Δ = 81000012
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{81000012}=\sqrt{4*20250003}=\sqrt{4}*\sqrt{20250003}=2\sqrt{20250003}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9000)-2\sqrt{20250003}}{2*3}=\frac{9000-2\sqrt{20250003}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9000)+2\sqrt{20250003}}{2*3}=\frac{9000+2\sqrt{20250003}}{6} $
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