x-1/2x+2+x+2/x+3=x+4/(x+2)(x+3)

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Solution for x-1/2x+2+x+2/x+3=x+4/(x+2)(x+3) equation: 



x-1/2x+2+x+2/x+3=x+4/(x+2)(x+3)

We move all terms to the left:

x-1/2x+2+x+2/x+3-(x+4/(x+2)(x+3))=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: x!=0

x∈R





Domain of the equation: (x+2)(x+3))!=0

x∈R



We add all the numbers together, and all the variables

2x-1/2x+2/x-(x+4/(x+2)(x+3))+5=0

We multiply parentheses ..

-(x+4/(+x^2+3x+2x+6))+2x-1/2x+2/x+5=0

We calculate fractions

We do not support expression: x^3

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