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x-1/10x=360
We move all terms to the left:
x-1/10x-(360)=0
Domain of the equation: 10x!=0We multiply all the terms by the denominator
x!=0/10
x!=0
x∈R
x*10x-360*10x-1=0
Wy multiply elements
10x^2-3600x-1=0
a = 10; b = -3600; c = -1;
Δ = b2-4ac
Δ = -36002-4·10·(-1)
Δ = 12960040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12960040}=\sqrt{4*3240010}=\sqrt{4}*\sqrt{3240010}=2\sqrt{3240010}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3600)-2\sqrt{3240010}}{2*10}=\frac{3600-2\sqrt{3240010}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3600)+2\sqrt{3240010}}{2*10}=\frac{3600+2\sqrt{3240010}}{20} $
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