x-1*2x-2*(-1)*3x-x-1*(-1)*x+1-x*1*3x=3x*(-x)-4*2x

Solution for x-1*2x-2*(-1)*3x-x-1*(-1)*x+1-x*1*3x=3x*(-x)-4*2x equation:

x-1*2x-2(-1)*3x-x-1(-1)*x+1-x*1*3x=3x(-x)-4*2x

We move all terms to the left:

x-1*2x-2(-1)*3x-x-1(-1)*x+1-x*1*3x-(3x(-x)-4*2x)=0

We add all the numbers together, and all the variables

x-1*2x-2(-1)*3x-x-1(-1)*x-x*1*3x-(3x(-1x)-4*2x)+1=0

We add all the numbers together, and all the variables

-1*2x-2(-1)*3x-1(-1)*x-x*1*3x-(3x(-1x)-4*2x)+1=0

We multiply parentheses

-1*2x+6x+1x-x*1*3x-(3x(-1x)-4*2x)+1=0

Wy multiply elements

-3x^2*3-2x+6x+1x-(3x(-1x)-4*2x)+1=0


We calculate terms in parentheses: -(3x(-1x)-4*2x), so:

3x(-1x)-4*2x

We multiply parentheses

-3x^2-4*2x

Wy multiply elements

-3x^2-8x

Back to the equation:

-(-3x^2-8x)


We add all the numbers together, and all the variables

-3x^2*3-(-3x^2-8x)+5x+1=0

Wy multiply elements

-9x^2-(-3x^2-8x)+5x+1=0

We get rid of parentheses

-9x^2+3x^2+8x+5x+1=0

We add all the numbers together, and all the variables

-6x^2+13x+1=0

a = -6; b = 13; c = +1;
Δ = b2-4ac
Δ = 132-4·(-6)·1
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{193}}{2*-6}=\frac{-13-\sqrt{193}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{193}}{2*-6}=\frac{-13+\sqrt{193}}{-12}
$