x-(x+1)+2*(3x-1)=2(x+1)-2

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Solution for x-(x+1)+2*(3x-1)=2(x+1)-2 equation: 



x-(x+1)+2(3x-1)=2(x+1)-2

We move all terms to the left:

x-(x+1)+2(3x-1)-(2(x+1)-2)=0

We multiply parentheses

x-(x+1)+6x-(2(x+1)-2)-2=0

We get rid of parentheses

x-x+6x-(2(x+1)-2)-1-2=0



We calculate terms in parentheses: -(2(x+1)-2), so:

2(x+1)-2

We multiply parentheses

2x+2-2

We add all the numbers together, and all the variables

2x

Back to the equation:

-(2x)



We add all the numbers together, and all the variables

4x-3=0

We move all terms containing x to the left, all other terms to the right

4x=3

x=3/4

x=3/4

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