x-(6x+1)/8=(3x-5)/12

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Solution for x-(6x+1)/8=(3x-5)/12 equation: 



x-(6x+1)/8=(3x-5)/12

We move all terms to the left:

x-(6x+1)/8-((3x-5)/12)=0

We calculate fractions


x+(-6x)/()+(-((3x-5)*8)/()=0



We calculate terms in parentheses: +(-((3x-5)*8)/(), so:

-((3x-5)*8)/(

We multiply all the terms by the denominator


-((3x-5)*8)



We calculate terms in parentheses: -((3x-5)*8), so:

(3x-5)*8

We multiply parentheses

24x-40

Back to the equation:

-(24x-40)



We get rid of parentheses

-24x+40

Back to the equation:

+(-24x+40)



We get rid of parentheses

x+(-6x)/()-24x+40=0

We multiply all the terms by the denominator


x*()+(-6x)-24x*()+40*()=0

We add all the numbers together, and all the variables

x*()+(-6x)-24x*()=0

We get rid of parentheses

x*()-6x-24x*()=0

We add all the numbers together, and all the variables

-6x+x*()-24x*()=0

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