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x-(1/2x+5)=31
We move all terms to the left:
x-(1/2x+5)-(31)=0
Domain of the equation: 2x+5)!=0We get rid of parentheses
x∈R
x-1/2x-5-31=0
We multiply all the terms by the denominator
x*2x-5*2x-31*2x-1=0
Wy multiply elements
2x^2-10x-62x-1=0
We add all the numbers together, and all the variables
2x^2-72x-1=0
a = 2; b = -72; c = -1;
Δ = b2-4ac
Δ = -722-4·2·(-1)
Δ = 5192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5192}=\sqrt{4*1298}=\sqrt{4}*\sqrt{1298}=2\sqrt{1298}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-2\sqrt{1298}}{2*2}=\frac{72-2\sqrt{1298}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+2\sqrt{1298}}{2*2}=\frac{72+2\sqrt{1298}}{4} $
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