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x+x+3/2x=45
We move all terms to the left:
x+x+3/2x-(45)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
2x+3/2x-45=0
We multiply all the terms by the denominator
2x*2x-45*2x+3=0
Wy multiply elements
4x^2-90x+3=0
a = 4; b = -90; c = +3;
Δ = b2-4ac
Δ = -902-4·4·3
Δ = 8052
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8052}=\sqrt{4*2013}=\sqrt{4}*\sqrt{2013}=2\sqrt{2013}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-2\sqrt{2013}}{2*4}=\frac{90-2\sqrt{2013}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+2\sqrt{2013}}{2*4}=\frac{90+2\sqrt{2013}}{8} $
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