x+x+(x+12)+(3x-19)=117

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Solution for x+x+(x+12)+(3x-19)=117 equation: 



x+x+(x+12)+(3x-19)=117

We move all terms to the left:

x+x+(x+12)+(3x-19)-(117)=0

We add all the numbers together, and all the variables

2x+(x+12)+(3x-19)-117=0

We get rid of parentheses

2x+x+3x+12-19-117=0

We add all the numbers together, and all the variables

6x-124=0

We move all terms containing x to the left, all other terms to the right

6x=124

x=124/6

x=20+2/3

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