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x+x+(4x-3x^2)=24
We move all terms to the left:
x+x+(4x-3x^2)-(24)=0
We add all the numbers together, and all the variables
(4x-3x^2)+2x-24=0
We get rid of parentheses
-3x^2+4x+2x-24=0
We add all the numbers together, and all the variables
-3x^2+6x-24=0
a = -3; b = 6; c = -24;
Δ = b2-4ac
Δ = 62-4·(-3)·(-24)
Δ = -252
Delta is less than zero, so there is no solution for the equation
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