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x+9/x=9
We move all terms to the left:
x+9/x-(9)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
x*x-9*x+9=0
We add all the numbers together, and all the variables
-9x+x*x+9=0
Wy multiply elements
x^2-9x+9=0
a = 1; b = -9; c = +9;
Δ = b2-4ac
Δ = -92-4·1·9
Δ = 45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{45}=\sqrt{9*5}=\sqrt{9}*\sqrt{5}=3\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3\sqrt{5}}{2*1}=\frac{9-3\sqrt{5}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3\sqrt{5}}{2*1}=\frac{9+3\sqrt{5}}{2} $
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