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x+9/9=3/x-8
We move all terms to the left:
x+9/9-(3/x-8)=0
Domain of the equation: x-8)!=0We add all the numbers together, and all the variables
x∈R
x-(3/x-8)+1=0
We get rid of parentheses
x-3/x+8+1=0
We multiply all the terms by the denominator
x*x+8*x+1*x-3=0
We add all the numbers together, and all the variables
9x+x*x-3=0
Wy multiply elements
x^2+9x-3=0
a = 1; b = 9; c = -3;
Δ = b2-4ac
Δ = 92-4·1·(-3)
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{93}}{2*1}=\frac{-9-\sqrt{93}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{93}}{2*1}=\frac{-9+\sqrt{93}}{2} $
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