x+8=(1/2)3x-10

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Solution for x+8=(1/2)3x-10 equation: 



x+8=(1/2)3x-10

We move all terms to the left:

x+8-((1/2)3x-10)=0



Domain of the equation: 2)3x-10)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

x-((+1/2)3x-10)+8=0

We multiply all the terms by the denominator


x*2)3x-10)-((+8*2)3x-10)+1=0

We add all the numbers together, and all the variables

x*2)3x-10)-(163x-10)+1=0

Wy multiply elements

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$

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