x+8/x-3=5/2

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Solution for x+8/x-3=5/2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+8/x-3 = 5/2 // - 5/2

x+8/x-(5/2)-3 = 0

x+8/x-5/2-3 = 0

1*x^1+8*x^-1-11/2*x^0 = 0

(1*x^2-11/2*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2-11/2*x^1+8*x^0) = 0

x^1

x^2+(-11/2)*x+8 = 0

x^2+(-11/2)*x+8 = 0

DELTA = (-11/2)^2-(1*4*8)

DELTA = -7/4

DELTA < 0

x in { } 

x belongs to the empty set

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