x+6x2=20

Solution for x+6x2=20 equation:

x+6x^2=20

We move all terms to the left:

x+6x^2-(20)=0

a = 6; b = 1; c = -20;
Δ = b2-4ac
Δ = 12-4·6·(-20)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{481}}{2*6}=\frac{-1-\sqrt{481}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{481}}{2*6}=\frac{-1+\sqrt{481}}{12}
$