x+6(x-3)=2(3x-2)

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Solution for x+6(x-3)=2(3x-2) equation: 



x+6(x-3)=2(3x-2)

We move all terms to the left:

x+6(x-3)-(2(3x-2))=0

We multiply parentheses

x+6x-(2(3x-2))-18=0



We calculate terms in parentheses: -(2(3x-2)), so:

2(3x-2)

We multiply parentheses

6x-4

Back to the equation:

-(6x-4)



We add all the numbers together, and all the variables

7x-(6x-4)-18=0

We get rid of parentheses

7x-6x+4-18=0

We add all the numbers together, and all the variables

x-14=0

We move all terms containing x to the left, all other terms to the right

x=14

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