x+5=2/1x+1

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Solution for x+5=2/1x+1 equation:



x+5=2/1x+1
We move all terms to the left:
x+5-(2/1x+1)=0
Domain of the equation: 1x+1)!=0
x∈R
We get rid of parentheses
x-2/1x-1+5=0
We multiply all the terms by the denominator
x*1x-1*1x+5*1x-2=0
Wy multiply elements
x^2-1x+5x-2=0
We add all the numbers together, and all the variables
x^2+4x-2=0
a = 1; b = 4; c = -2;
Δ = b2-4ac
Δ = 42-4·1·(-2)
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{6}}{2*1}=\frac{-4-2\sqrt{6}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{6}}{2*1}=\frac{-4+2\sqrt{6}}{2} $

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