x+5/20(100)=(3x-50)/3

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Solution for x+5/20(100)=(3x-50)/3 equation: 



x+5/20(100)=(3x-50)/3

We move all terms to the left:

x+5/20(100)-((3x-50)/3)=0

We calculate fractions


x+(-((3x-50)*20100)/()+()/()=0



We calculate terms in parentheses: +(-((3x-50)*20100)/()+()/(), so:

-((3x-50)*20100)/()+()/(

We add all the numbers together, and all the variables

-((3x-50)*20100)/()+1

We multiply all the terms by the denominator


-((3x-50)*20100)+1*()



We calculate terms in parentheses: -((3x-50)*20100), so:

(3x-50)*20100

We multiply parentheses

60300x-1005000

Back to the equation:

-(60300x-1005000)



We add all the numbers together, and all the variables

-(60300x-1005000)

We get rid of parentheses

-60300x+1005000

Back to the equation:

+(-60300x+1005000)



We get rid of parentheses

x-60300x+1005000=0

We add all the numbers together, and all the variables

-60299x+1005000=0

We move all terms containing x to the left, all other terms to the right

-60299x=-1005000

x=-1005000/-60299

x=16+40216/60299

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