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x+4/4x+16=0
Domain of the equation: 4x!=0We multiply all the terms by the denominator
x!=0/4
x!=0
x∈R
x*4x+16*4x+4=0
Wy multiply elements
4x^2+64x+4=0
a = 4; b = 64; c = +4;
Δ = b2-4ac
Δ = 642-4·4·4
Δ = 4032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4032}=\sqrt{576*7}=\sqrt{576}*\sqrt{7}=24\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-24\sqrt{7}}{2*4}=\frac{-64-24\sqrt{7}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+24\sqrt{7}}{2*4}=\frac{-64+24\sqrt{7}}{8} $
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