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x+4/3x=84
We move all terms to the left:
x+4/3x-(84)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
x*3x-84*3x+4=0
Wy multiply elements
3x^2-252x+4=0
a = 3; b = -252; c = +4;
Δ = b2-4ac
Δ = -2522-4·3·4
Δ = 63456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{63456}=\sqrt{16*3966}=\sqrt{16}*\sqrt{3966}=4\sqrt{3966}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-252)-4\sqrt{3966}}{2*3}=\frac{252-4\sqrt{3966}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-252)+4\sqrt{3966}}{2*3}=\frac{252+4\sqrt{3966}}{6} $
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