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x+4/3x-1=-4
We move all terms to the left:
x+4/3x-1-(-4)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x+4/3x+3=0
We multiply all the terms by the denominator
x*3x+3*3x+4=0
Wy multiply elements
3x^2+9x+4=0
a = 3; b = 9; c = +4;
Δ = b2-4ac
Δ = 92-4·3·4
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{33}}{2*3}=\frac{-9-\sqrt{33}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{33}}{2*3}=\frac{-9+\sqrt{33}}{6} $
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