x+4+4x+10(x-1)=288

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Solution for x+4+4x+10(x-1)=288 equation:



x+4+4x+10(x-1)=288
We move all terms to the left:
x+4+4x+10(x-1)-(288)=0
We add all the numbers together, and all the variables
5x+10(x-1)-284=0
We multiply parentheses
5x+10x-10-284=0
We add all the numbers together, and all the variables
15x-294=0
We move all terms containing x to the left, all other terms to the right
15x=294
x=294/15
x=19+3/5

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