x+4(x-2)=6x-1+8(2x+3)

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Solution for x+4(x-2)=6x-1+8(2x+3) equation: 



x+4(x-2)=6x-1+8(2x+3)

We move all terms to the left:

x+4(x-2)-(6x-1+8(2x+3))=0

We multiply parentheses

x+4x-(6x-1+8(2x+3))-8=0



We calculate terms in parentheses: -(6x-1+8(2x+3)), so:

6x-1+8(2x+3)

determiningTheFunctionDomain
6x+8(2x+3)-1

We multiply parentheses

6x+16x+24-1

We add all the numbers together, and all the variables

22x+23

Back to the equation:

-(22x+23)



We add all the numbers together, and all the variables

5x-(22x+23)-8=0

We get rid of parentheses

5x-22x-23-8=0

We add all the numbers together, and all the variables

-17x-31=0

We move all terms containing x to the left, all other terms to the right

-17x=31

x=31/-17

x=-1+14/17

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