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x+4(1-x)=2x-3(2-x)
We move all terms to the left:
x+4(1-x)-(2x-3(2-x))=0
We add all the numbers together, and all the variables
x+4(-1x+1)-(2x-3(-1x+2))=0
We multiply parentheses
x-4x-(2x-3(-1x+2))+4=0
We calculate terms in parentheses: -(2x-3(-1x+2)), so:We add all the numbers together, and all the variables
2x-3(-1x+2)
We multiply parentheses
2x+3x-6
We add all the numbers together, and all the variables
5x-6
Back to the equation:
-(5x-6)
-3x-(5x-6)+4=0
We get rid of parentheses
-3x-5x+6+4=0
We add all the numbers together, and all the variables
-8x+10=0
We move all terms containing x to the left, all other terms to the right
-8x=-10
x=-10/-8
x=1+1/4
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