x+3y=-6;y=1/2x-7

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2x+y=8
x+3y=14

Solution for x+3y=-6;y=1/2x-7 system of equations: 


  • /| x+3*y+6 = 0| y-((1/2)*x)+7 = 0
  • We try to solve the equation: x+3*y+6 = 0
  • x+3*y+6 = 0 // - x+6
  • 3*y = -(x+6) // : 3
  • y = (-(x+6))/3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (-(x+6))/3-((1/2)*x)+7 = 0| y = (-(x+6))/3
  • (-x-6)/3-x/2+7 = 0
  • 7-5/6*x-2 = 0
  • 5-5/6*x = 0
  • 5-5/6*x = 0 // - 5
  • -5/6*x = -5 // : -5/6
  • x = -5/(-5/6)
  • x = 6
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (-(x+6))/3: 
  • y = (-(6+6))/3
  • y = -12/3
  • y = -4
  • We get a system of equations:
  • /| y = -4| x = 6

 

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