x+3x+20=3(2x+4)

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Solution for x+3x+20=3(2x+4) equation: 



x+3x+20=3(2x+4)

We move all terms to the left:

x+3x+20-(3(2x+4))=0

We add all the numbers together, and all the variables

4x-(3(2x+4))+20=0



We calculate terms in parentheses: -(3(2x+4)), so:

3(2x+4)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

4x-6x-12+20=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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