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x+3=-2/3x-11
We move all terms to the left:
x+3-(-2/3x-11)=0
Domain of the equation: 3x-11)!=0We get rid of parentheses
x∈R
x+2/3x+11+3=0
We multiply all the terms by the denominator
x*3x+11*3x+3*3x+2=0
Wy multiply elements
3x^2+33x+9x+2=0
We add all the numbers together, and all the variables
3x^2+42x+2=0
a = 3; b = 42; c = +2;
Δ = b2-4ac
Δ = 422-4·3·2
Δ = 1740
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1740}=\sqrt{4*435}=\sqrt{4}*\sqrt{435}=2\sqrt{435}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-2\sqrt{435}}{2*3}=\frac{-42-2\sqrt{435}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+2\sqrt{435}}{2*3}=\frac{-42+2\sqrt{435}}{6} $
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