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x+30=5/3x+18
We move all terms to the left:
x+30-(5/3x+18)=0
Domain of the equation: 3x+18)!=0We get rid of parentheses
x∈R
x-5/3x-18+30=0
We multiply all the terms by the denominator
x*3x-18*3x+30*3x-5=0
Wy multiply elements
3x^2-54x+90x-5=0
We add all the numbers together, and all the variables
3x^2+36x-5=0
a = 3; b = 36; c = -5;
Δ = b2-4ac
Δ = 362-4·3·(-5)
Δ = 1356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1356}=\sqrt{4*339}=\sqrt{4}*\sqrt{339}=2\sqrt{339}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-2\sqrt{339}}{2*3}=\frac{-36-2\sqrt{339}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+2\sqrt{339}}{2*3}=\frac{-36+2\sqrt{339}}{6} $
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