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x+3-2=3(x+4)
We move all terms to the left:
x+3-2-(3(x+4))=0
We add all the numbers together, and all the variables
x-(3(x+4))+1=0
We calculate terms in parentheses: -(3(x+4)), so:We get rid of parentheses
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
x-3x-12+1=0
We add all the numbers together, and all the variables
-2x-11=0
We move all terms containing x to the left, all other terms to the right
-2x=11
x=11/-2
x=-5+1/2
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