x+3+x+3=(-x+4)+(3x-2)

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Solution for x+3+x+3=(-x+4)+(3x-2) equation:


Simplifying
x + 3 + x + 3 = (-1x + 4) + (3x + -2)

Reorder the terms:
3 + 3 + x + x = (-1x + 4) + (3x + -2)

Combine like terms: 3 + 3 = 6
6 + x + x = (-1x + 4) + (3x + -2)

Combine like terms: x + x = 2x
6 + 2x = (-1x + 4) + (3x + -2)

Reorder the terms:
6 + 2x = (4 + -1x) + (3x + -2)

Remove parenthesis around (4 + -1x)
6 + 2x = 4 + -1x + (3x + -2)

Reorder the terms:
6 + 2x = 4 + -1x + (-2 + 3x)

Remove parenthesis around (-2 + 3x)
6 + 2x = 4 + -1x + -2 + 3x

Reorder the terms:
6 + 2x = 4 + -2 + -1x + 3x

Combine like terms: 4 + -2 = 2
6 + 2x = 2 + -1x + 3x

Combine like terms: -1x + 3x = 2x
6 + 2x = 2 + 2x

Add '-2x' to each side of the equation.
6 + 2x + -2x = 2 + 2x + -2x

Combine like terms: 2x + -2x = 0
6 + 0 = 2 + 2x + -2x
6 = 2 + 2x + -2x

Combine like terms: 2x + -2x = 0
6 = 2 + 0
6 = 2

Solving
6 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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