x+3(7x-4)=8x-40

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Solution for x+3(7x-4)=8x-40 equation: 



x+3(7x-4)=8x-40

We move all terms to the left:

x+3(7x-4)-(8x-40)=0

We multiply parentheses

x+21x-(8x-40)-12=0

We get rid of parentheses

x+21x-8x+40-12=0

We add all the numbers together, and all the variables

14x+28=0

We move all terms containing x to the left, all other terms to the right

14x=-28

x=-28/14

x=-2

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