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x+3(2x-1)=8-5(3-x)
We move all terms to the left:
x+3(2x-1)-(8-5(3-x))=0
We add all the numbers together, and all the variables
x+3(2x-1)-(8-5(-1x+3))=0
We multiply parentheses
x+6x-(8-5(-1x+3))-3=0
We calculate terms in parentheses: -(8-5(-1x+3)), so:We add all the numbers together, and all the variables
8-5(-1x+3)
determiningTheFunctionDomain -5(-1x+3)+8
We multiply parentheses
5x-15+8
We add all the numbers together, and all the variables
5x-7
Back to the equation:
-(5x-7)
7x-(5x-7)-3=0
We get rid of parentheses
7x-5x+7-3=0
We add all the numbers together, and all the variables
2x+4=0
We move all terms containing x to the left, all other terms to the right
2x=-4
x=-4/2
x=-2
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