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x+2x+1/2x=224
We move all terms to the left:
x+2x+1/2x-(224)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
3x+1/2x-224=0
We multiply all the terms by the denominator
3x*2x-224*2x+1=0
Wy multiply elements
6x^2-448x+1=0
a = 6; b = -448; c = +1;
Δ = b2-4ac
Δ = -4482-4·6·1
Δ = 200680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{200680}=\sqrt{4*50170}=\sqrt{4}*\sqrt{50170}=2\sqrt{50170}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-448)-2\sqrt{50170}}{2*6}=\frac{448-2\sqrt{50170}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-448)+2\sqrt{50170}}{2*6}=\frac{448+2\sqrt{50170}}{12} $
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