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x+2=3/10x
We move all terms to the left:
x+2-(3/10x)=0
Domain of the equation: 10x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+3/10x)+2=0
We get rid of parentheses
x-3/10x+2=0
We multiply all the terms by the denominator
x*10x+2*10x-3=0
Wy multiply elements
10x^2+20x-3=0
a = 10; b = 20; c = -3;
Δ = b2-4ac
Δ = 202-4·10·(-3)
Δ = 520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{520}=\sqrt{4*130}=\sqrt{4}*\sqrt{130}=2\sqrt{130}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-2\sqrt{130}}{2*10}=\frac{-20-2\sqrt{130}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+2\sqrt{130}}{2*10}=\frac{-20+2\sqrt{130}}{20} $
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