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x+2=-3x(x+1)
We move all terms to the left:
x+2-(-3x(x+1))=0
We calculate terms in parentheses: -(-3x(x+1)), so:We get rid of parentheses
-3x(x+1)
We multiply parentheses
-3x^2-3x
Back to the equation:
-(-3x^2-3x)
3x^2+3x+x+2=0
We add all the numbers together, and all the variables
3x^2+4x+2=0
a = 3; b = 4; c = +2;
Δ = b2-4ac
Δ = 42-4·3·2
Δ = -8
Delta is less than zero, so there is no solution for the equation
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