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x+23=x2-43
We move all terms to the left:
x+23-(x2-43)=0
We add all the numbers together, and all the variables
-(+x^2-43)+x+23=0
We get rid of parentheses
-x^2+x+43+23=0
We add all the numbers together, and all the variables
-1x^2+x+66=0
a = -1; b = 1; c = +66;
Δ = b2-4ac
Δ = 12-4·(-1)·66
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{265}}{2*-1}=\frac{-1-\sqrt{265}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{265}}{2*-1}=\frac{-1+\sqrt{265}}{-2} $
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