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x+21-1/3x=9
We move all terms to the left:
x+21-1/3x-(9)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x-1/3x+12=0
We multiply all the terms by the denominator
x*3x+12*3x-1=0
Wy multiply elements
3x^2+36x-1=0
a = 3; b = 36; c = -1;
Δ = b2-4ac
Δ = 362-4·3·(-1)
Δ = 1308
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1308}=\sqrt{4*327}=\sqrt{4}*\sqrt{327}=2\sqrt{327}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-2\sqrt{327}}{2*3}=\frac{-36-2\sqrt{327}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+2\sqrt{327}}{2*3}=\frac{-36+2\sqrt{327}}{6} $
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