x+2/x-2-x-2/x+2=5/6

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Solution for x+2/x-2-x-2/x+2=5/6 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x-x+2/x-(2/x)-2+2 = 5/6 // - 5/6

x-x+2/x-(2/x)-(5/6)-2+2 = 0

x-x+2/x-2*x^-1-5/6-2+2 = 0

-5/6 = 0

x belongs to the empty set

x belongs to the empty set

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