x+2(x-3)=3(x-2)

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Solution for x+2(x-3)=3(x-2) equation: 



x+2(x-3)=3(x-2)

We move all terms to the left:

x+2(x-3)-(3(x-2))=0

We multiply parentheses

x+2x-(3(x-2))-6=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

3x-(3x-6)-6=0

We get rid of parentheses

3x-3x+6-6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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